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Subtract 10 days from a date and return the date:
SELECT SUBDATE("2017-06-15", INTERVAL 10 DAY);Formula
The SUBDATE() function subtracts a time/date interval from a date and then returns the date.date, INTERVAL value unit )
date, days )
Required. The original date days Required. The number of days to subtract from date value
Formula
Required. The value of the time/date interval to subtract. Both positive and negative values are allowed unitRequired. The type of interval. Can be one of the following values: MICROSECOND SECOND MINUTE HOUR DAY WEEK MONTH QUARTER
SECOND_MICROSECOND MINUTE_MICROSECOND MINUTE_SECOND HOUR_MICROSECOND HOUR_SECOND HOUR_MINUTE DAY_MICROSECOND DAY_SECOND DAY_MINUTE DAY_HOUR YEAR_MONTH
From MySQL 4.0
Subtract 15 minutes from a date and return the date: SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 15 MINUTE);
Subtract 3 hours from a date and return the date: SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 3 HOUR);
Add 2 months to a date and return the date:
SELECT SUBDATE("2017-06-15", INTERVAL -2 MONTH);❮ MySQL Functions